-36x^2+24x=0

Solution for -36x^2+24x=0 equation:

-36x^2+24x=0

a = -36; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-36)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-36}=\frac{-48}{-72}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-36}=\frac{0}{-72}
=0
$